752. Un alcool polihidroxilic aciclic saturat reactioneaza cu un acid monocarboxilic aciclic saturat ,formand esterul cu masa mol 302 care contine de 5 ori mai multi at de C decat alc. Stiind ca acidul are fata de alcool un at de C in plus,alcoolul si acidul sunt :
A. 1,2-propandiolul, acid butanoic
B. 1,2,3-propantriolul, acid butanoic
C. etilenglicolul, acid propanoic
D.1,2,3-butantriolul, acidul pentanoic
E. glicerol, acid butanoic
Ma intereseaza daca aceasta problema se poate rezolva si altfel sau numai printr-o ecuatie de gradul al II-lea. Multumesc anticipat!
Analizam itemii si vedem ca alcoolu nostru poate avea doar 2 sau 3 atomi de C
Formula moleculara a alcolului este CnH2n+2Ox,a acidului este Cn+1H2n+2O2.
In urma polimerizarii se va obtine un ester ce a inglobat x*(n+1) atomi de C(cate un n+1 atomi pentru fiecare oxigen.Deci esterul nostru va aveam n+nx+x atomi de C.
5n=n+nx+x=>4n=x(n+1)=>x=4n/(n+1).Acum noi stim ca n si x sunt numere naturale deci n+1 trebuie sa divida 4n si n .
n=1 Fals fiindca nu corespunde vreunei grile
n=2 => x=8/3 care nu este numar natural
n=3=> x=3 ,=> Alcolul cautat este glicreolul iar acidul cautat este acidul butanoic.
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